Grade 11 Robotics Worksheet: Forces — Challenge Practice

Forces Challenge Practice

Grade 11 Robotics Forces Challenge Practice Challenging 25 Questions 10 Views

Classroom Worksheet

Grade 11 Robotics Worksheet: Forces — Challenge Practice

Forces Challenge Practice

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Grade: Grade 11

Subject: Robotics

Topic: Forces

Time: 20 Minutes

Difficulty: Challenging

Questions: 25

Instructions:
Instructions: Answer all 25 questions. Show your work where needed, include units in every calculation, and explain your reasoning clearly. Use correct robotics and physics vocabulary. The questions increase in difficulty, so take your time and check each answer before moving on.

Skills Practiced:

Forces
Robotics
Critical Thinking
Problem Solving

1Question

Define force in the context of robotics and give one example of a force acting on a robot.

2Question

State Newton’s First Law of Motion and describe what it means for a robot that is not moving.

3Question

A robot arm lifts a 2 kg part straight upward at constant speed. What is the approximate upward force needed just to balance the weight of the part? Use g = 9.8 m/s².

4Question

A mobile robot pushes a crate with 12 N to the right while friction pushes back with 5 N to the left. What is the net force on the crate?

5Question

A 4 kg robot experiences a net force of 8 N. What is its acceleration?

6Question

A robot of mass 10 kg accelerates at 1.5 m/s². What net force is required?

7Question

A robot arm applies a force of 30 N over a distance of 0.5 m in the same direction as the motion. What work is done?

8Question

Two motors each pull a robot forward with 18 N. Friction and drag together oppose motion with 22 N. What is the net force?

9Question

A 6 kg robot starts from rest and reaches 3 m/s in 2 s. What is its average acceleration?

10Question

Using the acceleration from Question 9, what net force acted on the 6 kg robot?

11Question

A robot gripper holds a 0.8 kg object motionless. What upward force must the gripper provide to balance the object’s weight?

12Question

A drivetrain has a total forward motor force of 50 N. The robot’s total resistive forces are 32 N. What is the robot’s net force and direction?

13Question

A 3 kg robot has a net force of 12 N on a smooth floor. How far will it travel in 4 s if it starts from rest?

14Question

A robot arm must lift a 5 kg component upward at constant speed. What lifting force is needed, and why is it not greater than the weight in this case?

15Question

A wheeled robot experiences a forward force of 70 N and a backward friction force of 28 N. If its mass is 7 kg, what is its acceleration?

16Question

A robot moves with constant velocity across a flat surface. List two forces that may still be acting on the robot and explain how they must compare.

17Question

A 20 kg robot is pushed with a net force of 40 N. How long will it take to increase its speed from 2 m/s to 10 m/s, assuming the force stays constant?

18Question

A robotic arm rotates a tool using a force of 15 N applied perpendicular to a 0.3 m arm. What torque is produced?

19Question

A robot must generate 6 N·m of torque using a 0.2 m arm. What force is needed if the force is applied perpendicular to the arm?

20Question

A delivery robot has a mass of 12 kg. The motor provides 60 N forward, while friction is 18 N backward. Calculate the robot’s acceleration and explain whether the robot speeds up or slows down if it is already moving forward.

21Question

A robot lifts a 4 kg object vertically by 2 m at constant speed. Calculate the work done against gravity.

22Question

A robot arm exerts a force of 50 N at an angle perpendicular to a lever of length 0.4 m. What is the torque? If the force were applied at half the perpendicular distance, what would the torque be?

23Question

A 5 kg robot starts from rest and experiences a constant net force of 10 N for 6 s. Find its final speed and the distance traveled in that time.

24Question

A robot uses two side-by-side motors to move forward. Motor A provides 24 N, Motor B provides 18 N, and total resistance is 9 N backward. The robot mass is 9 kg. Find the net force and acceleration. Then explain why one motor failing would affect the robot’s motion.

25Question

Design challenge: A 15 kg autonomous robot must accelerate from 0 to 4 m/s in 2 s on a floor where friction is 12 N backward. What forward force must the drive system produce? Show all steps and explain how this force changes if the robot’s mass increases to 18 kg while the same acceleration is required.

Answer Key

#	Answer
1	Force is a push or pull that can change an object’s motion or shape. Example: friction acting between a robot’s wheel and the floor.
2	Newton’s First Law says an object at rest stays at rest and an object in motion stays in motion at constant velocity unless acted on by a net force. For a robot that is not moving, it will remain still unless a force causes it to move.
3	Weight = mg = 2 × 9.8 = 19.6 N. The upward force needed is 19.6 N.
4	Net force = 12 N - 5 N = 7 N to the right.
5	Using F = ma, a = F/m = 8/4 = 2 m/s².
6	F = ma = 10 × 1.5 = 15 N.
7	Work = Fd = 30 × 0.5 = 15 J.
8	Forward force = 36 N. Net force = 36 - 22 = 14 N forward.
9	a = (v - u)/t = (3 - 0)/2 = 1.5 m/s².
10	F = ma = 6 × 1.5 = 9 N.
11	Weight = 0.8 × 9.8 = 7.84 N. The gripper must provide 7.84 N upward.
12	Net force = 50 - 32 = 18 N forward.
13	First find acceleration: a = F/m = 12/3 = 4 m/s². Then s = 1/2 at² = 0.5 × 4 × 16 = 32 m.
14	Lifting force = weight = 5 × 9.8 = 49 N. It is not greater because constant speed means acceleration is zero, so net force must be zero.
15	Net force = 70 - 28 = 42 N. Acceleration = 42/7 = 6 m/s².
16	Examples: motor driving force and friction force, or weight and normal force. They must be equal in size and opposite in direction so the net force is zero.
17	Acceleration = 40/20 = 2 m/s². Time = (10 - 2)/2 = 4 s.
18	Torque = force × distance = 15 × 0.3 = 4.5 N·m.
19	Force = torque/distance = 6/0.2 = 30 N.
20	Net force = 60 - 18 = 42 N. Acceleration = 42/12 = 3.5 m/s² forward. If already moving forward, it speeds up.
21	Weight = 4 × 9.8 = 39.2 N. Work = Fd = 39.2 × 2 = 78.4 J.
22	First torque = 50 × 0.4 = 20 N·m. At half the distance, torque = 50 × 0.2 = 10 N·m.
23	Acceleration = 10/5 = 2 m/s². Final speed = at = 2 × 6 = 12 m/s. Distance = 1/2 at² = 0.5 × 2 × 36 = 36 m.
24	Total forward force = 24 + 18 = 42 N. Net force = 42 - 9 = 33 N forward. Acceleration = 33/9 = 3.67 m/s². If one motor fails, total forward force drops, so net force and acceleration both decrease.
25	Required acceleration = (4 - 0)/2 = 2 m/s². For 15 kg: net force = ma = 15 × 2 = 30 N. Since friction is 12 N backward, drive force must be 30 + 12 = 42 N forward. If mass increases to 18 kg, net force needed = 18 × 2 = 36 N, so drive force must be 36 + 12 = 48 N forward.