Electricity Homework Practice
| # | Answer |
|---|---|
| 1 | The rate of flow of electric charge through a circuit. |
| 2 | ampere (A) |
| 3 | volt (V) |
| 4 | ohm (Ω) |
| 5 | Electrons |
| 6 | Ions |
| 7 | I = Q / t |
| 8 | I = Q/t = 12/3 = 4 A |
| 9 | Q = It = 2 × 10 = 20 C |
| 10 | The potential difference across a conductor is directly proportional to the current through it, provided temperature and other physical conditions remain constant. |
| 11 | R = V / I |
| 12 | R = V/I = 9/3 = 3 Ω |
| 13 | V = IR = 0.5 × 8 = 4 V |
| 14 | A substance that conducts electricity when molten or in aqueous solution because it contains mobile ions. |
| 15 | In solid sodium chloride the ions are fixed in a crystal lattice and cannot move; when molten, the ions are free to move and carry charge. |
| 16 | A material that allows electric charge to flow easily because it has mobile charge carriers. |
| 17 | No. Distilled water has very few ions, so it is a very poor conductor. |
| 18 | Cu2+ ions move to the cathode and gain electrons; SO4^2− ions move to the anode, although they often remain spectator ions depending on the electrode and conditions. |
| 19 | The decomposition of an ionic compound by the passage of an electric current through it when molten or in solution. |
| 20 | Cathode |
| 21 | Anode |
| 22 | Positive |
| 23 | Negative |
| 24 | Cu2+ + 2e− → Cu |
| 25 | 2Cl− → Cl2 + 2e− |
| 26 | Lead metal |
| 27 | Bromine |
| 28 | Q = It = 1.5 × 2400 = 3600 C |
| 29 | Q = It = 0.80 × 1500 = 1200 C |
| 30 | n = Q/F = 9650/96500 = 0.10 mol e− |
| 31 | 2.0 mol e− |
| 32 | 1.0 mol Cu is deposited, so mass = 63.5 g |
| 33 | 0.50 mol Cu2+ requires 1.0 mol e−, because Cu2+ + 2e− → Cu |
| 34 | mass = 0.25 × 63.5 = 15.875 g, approximately 15.9 g |
| 35 | 0.30 mol e− deposits 0.15 mol Cu, because 2 mol e− deposit 1 mol Cu |
| 36 | Q = It = 2.0 × 9650 = 19300 C; n = Q/F = 19300/96500 = 0.20 mol e− |
| 37 | 0.20 mol e− deposits 0.10 mol Cu |
| 38 | mass = 0.10 × 63.5 = 6.35 g |
| 39 | Because the electrolysis reaction is non-spontaneous and requires electrical energy to force electrons through the circuit and drive the decomposition reaction. |
| 40 | At the cathode, magnesium metal forms because Mg2+ ions gain electrons. At the anode, chlorine gas forms because Cl− ions lose electrons. The ions move to opposite electrodes according to their charges during electrolysis. |